Syntel Practice Aptitude Problems



Dear Reader, Below are three easy aptitude problems for your practice.

Question 1

Mr. Venkata Ramana, working as a software engineer in a leading IT firm in Chennai took two days leave and went to Tiruvannamalai. Places he visited comprises Arunachaleswara Temple and Ramanashram. He noticed that there were a lot of monkeys near the temple gopuram.(tower). The tower was 136 metres height in all. A male monkey was trying to go up and he was brought down by a female monkey. This was happening with a regularity. For the first 30 seconds the male monkey was climbing up 10 metres and in the next 30 seconds the female monkey brought down the male monkey by 4 metres. This process was going on. Mr.Venkata Ramana took his video camera and was recording what was happening. He wanted to see whether the male monkey will reach the top of the Tower and if so how long it takes for it to reach the top. How long the male monkey would have taken to reach the top of the tower?

a) 22 ½ mts. b) 20 ½ mts c) 24 mts d) 21 ½ mts.

Answer : d) 21 ½ mts.

Solution :

At the end of 30 seconds the male monkey goes up by 10 metres and at the end of one minute the male comes down by four metres and hence in one minute it goes up by 6 metres. If this process continues like this the monkey will take 21 minutes to reach 126 metre height. (21 x 6 = 126.) And in the next half minute the male monkey will reach the top of the gopuram(tower) i.e. 136 metre.
(Though these types of problems take lot of time to read, the problem is a very simple one. The point is that you shouldn't be misled by the length of the question.)

Question 2

Reddyappa was keen on finding treasures in a forest in Karnataka State. He wanted to take up this exercise alone so that he will get all the treasures. He was told that during Tipu Sultan’s period he had gone inside the forest and hidden huge treasures inside a well. He started late 3 at night one day and entered the dark forest. He took a bright torch light with him for guiding him inside the forest. One the first day he walked about 20 km and reach a spot where he found a deep well. There was no water in the well. The depth of the well was 249 feet. He was trying locate ways for getting down inside the well to ascertain whether treasure was there. At that time he saw big frog –fairly big and strong enough trying to climb up to the ground. The frog was initially at the ground and it was climbing up in steps. In the first step the frog climbed up 7 feet but in the second step it was getting dropped by 1 1/2 feet. This process was going on. How many steps the frog would have taken to reach the top of the well/ground?

a) 22 steps b) 45 steps c) 28 steps d) 48.

Answer : b) 45 steps.

Solution :

Important point is about frog climbing up in steps. Other details are given to see whether the candidate is able to differentiate between wanted and unwanted material.
In the first step the frog climbs up 7 feet. In the second step it goes down (gets dropped) by 1 ½ feet. So in every steps the frog will be moving up by 5 ½ feet. In 44 steps it will reach 242 feet from the bottom of the well (44 x 5 ½ = 242). In the 45th step the frog will be able to reach (242 + 7 = 249 , which is the height of the well. ) the top of the well or ground level.

Question 3

Govindasamy, the mason in-charge of a building construction company selected Champa a new labourer for work. Champa was asked to keep the bricks one over the other. Champa – since he was new for this type of work – constructed 9 bricks at a time in the first minute. In the next minute he use to re-adjust these bricks in the process was taking out three from them. He was continuing in this fashion. Govindasamy was keen that the work should be completed early. He was watching this new labourer repeating this process of working. How many bricks Champa would have constructed at the end of one hour 25 minutes from the start of the work?

a) 261 b)258 c)261 d) none of these.

Answer : c) 261

Solution :

This problem is also similar to the two previous problems.
In the first minute he constructs 9 bricks and in the second minute he re-adjusts and takes out 3 bricks. So at the end of every two minutes he would have constructed 6 bricks only.

Minutes   Bricks 2              6 84            ?

So in 84 minutes he would have constructed 252 bricks.(84 x 6/2 = 252 ) In the 85th minute he will construct nine more and would have done 261 bricks.


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