Below are three easy questions requiring you to formulate and solve equations.
Question 1
A gentleman had ‘Rs.P’ with him. He wanted to distribute this amount to his five sons. He wanted his youngest son to get Rs.20 more than his fourth son. He gave his third son Rs.20 less than what he gave to his fourth son. His second son got Rs.20 more than his first son and Rs.20 less than what his third son got. How much did his first son get?
a) (P-200)/5 b) (P- 120)/4 c) (P-200)/4 d) none of these.
Answer : a) (P-200)/5
Solution :
Let his first son get x.
Then second son will get x +20.
Third son will get x+40
Fourth son will get x+60
Fifth son will get x+80 (youngest son)
So x + (x+20) + (x+40) + (x+60) + (x+80) = P
5x + 200 = P
X = (P – 200) / 5
Question 2
A received 20% more salary than B. C received 20% more than A. D received 20% more than C. If D received salary of Rs.34560, how much did A receive as salary?
a) Rs.22000 b) Rs.24000 c) Rs.26000 d) Rs.20000
Answer : b) Rs.24000
Solution :
Let B receive Rs.100 as salary.
Then A will receive 20% more than B's salary. That is, A will receive, 120/100 x B's salary = 120/100 x 100 = Rs. 120
Thus, A will receive Rs.120
C will receive 20% more than A's salary. That is, C will receive, 120/100 x A's salary = 120/100 x 120 = Rs. 144
Thus, C will receive Rs.144
D will receive 20% more than C's salary. That is, D will receive, 120/100 x C's salary = 120/100 x 144 = Rs. 172.8
Thus, D will receive Rs.172.80
Now, we will have to find out the salary of A if D receives 34560 as salary. From our above assumption of B receiving Rs.100, we can see that D will receive Rs. 172.8 when A receives Rs.120. Our task is now to find A's salary when D receives 34560.
D's Salary A's Salary 172.8 120 34560 ?
A's Salary when D receives 34560 = 34560 x 120 divided by 172.80 = Rs. 24000
Question 3
Agarwal has twice as much money as Edgar. Edgar has 50% more than Prasad has. If the average of the amounts they have is Rs.1100, how much money Agarwal has?
a) Rs. 1800 B) Rs.2100 c) Rs.800 d) none of these.
Answer : a) Rs. 1800
Solution :
Let Prasad has Rs.P
Then Edgar will have 50% more than prasad. That is, Edgar will have 150/100 x Prasad's Amount = 150/100 x P = 3/2 P
Agarwal will have twice as much as Edgar. Therefore Agarwal willl have 3/2P x 2 = 3P
Average of their amounts = Sum of their amounts / 3 = Rs. 1100
Or Sum of their amounts = 1100 x 3 = 3300
Or 3P + 3/2P + P = 3300
11P/2 = 3300
P = Rs. 600
Agarwal's amount = 3P = 3 x 600 = Rs. 1800