Dear Visiter or Reader, Below are three logical aptitude problems for practice. First question is a simple one while the remaining ones would require a bit of logical application.
Question 1
A man climbs 12 m in the first step and falls back 4 m in the next step. The process continues. How many steps are required to reach the pole of 68 m?
a) 7 b) 15 c) 8 d) 16
Answer : b) 15
Solution :
In the first step the man climbs 12 m. In the second step he falls back 4 m.
So in every two steps the man will climb up 8 m.
The height of the pole is 68 m.
In 14 steps he will reach 56 m. (8 x 7)
Then in the 15th step he will climb up 12 m and reach the top of the pole-68m.
Question 2
In a thick forest there is an old damaged well. The depth of the well is 47 feet. An old frog was struck up at the bottom of the well. The friends and foes of this frog were on the ground. The frog attempted to climb up to the ground. The friends of frog encouraged the frog to climb up 7 feet in one minute. Thereafter the foes of frog discouraged and made the frog go down 3 feet in the next one minute. After 10 minutes, more friends start gathering and their encouragement helped the frog to climb 9 feet instead of 7 in each cycle. This process continued. How many minutes will it take for the frog to reach the top of the well?
a) 20 minutes b) 17 minutes c) 21 minutes d) none of these.
Answer : b) 17 minutes.
Solution :
The solution should be derived by splitting the time frame before and after 10 minutes.
For the first 10 minutes.
In the first minute the frog climbs up 7 feet.
In the second minute the frog goes down 3 feet.
In 2 minutes the frog will be 4 feet above the original spot.
Therefore, In the first 10 minutes, the frog would had climbed 20 feet. Lets say this spot as SPOT B.
From the 11th minute : (Note after 10 minutes, since the frog has already climbed 20 feet, there would be remaining 27 feet to climb)
In the first minute the frog climbs up 9 feet.
In the second minute the frog goes down 3 feet
In 2 minutes the frog will be 6 feet above the Spot B.
Therefore, In 6 minutes the frog will climb 18 feet above the Spot B.
In the 7th minute, it would climb 9 feet and would had reached the top (18 + 9 = 27) and go away.
Therefore the frog needs to climb for 10 + 7 = 17 minutes
Question 3
A male monkey and its pair were attempting to climb a tree of 93 metres. Both of them use to cooperate in the first minute and climb up 9 feet. In the second minute both the monkeys use to fight and climb down 5 feet. Will the monkeys be able to reach the top if the process continues like this and if so how many climb ups and climb downs would be required? ('climb up' refers to the action of monkeys climbing up in one stretch before climbing down. 'climb down' refers to the action of climbing down in one stretch before climbing up)
a) No.
b) Yes, 22 climb ups and 21 climb downs
c) Yes, 24 climb ups and 23 climb downs
d) None of these.
Answer : b) Yes, 22 climb ups and 21 climb downs
Solution :
In the first minute they climb up 9 feet.
In the second minute they climb down 5 feet.
So after two minutes the monkeys will be 4 feet above the original level.
In 42 minutes they will be 84 feet above the original level. In 42 minutes, there would 21 climb ups and 21 climb downs.
In the 43rd minute they will climb 9 feet and reach the top. In 43rd minute, there would be one climb up.
In total, the monkeys would reach the top after 22 climb ups and 21 climb downs