Below are few sample problems requiring you to measure distances by drawing diagrams. Hope this helps in your preparation
Question 1
Rahman Khan wanted to do exercise seriously. He started from his house and went eastwards 2 km. He turned right and proceeded running 25 km. He took rest for a few minutes there. Now he took a left turn and walked 15 km and stopped. He spent his night in that place and thereafter he started walking towards north 18 km. Here he took a right turn and ran for 7 km and reached his uncle’s house. How far is Rahman Khan’s uncle’s house from his house?
a) 24 km b) 20 km c) 16 km d) 25 km
Answer : d) 25 km.
Solution :
Apply pythagoras theorem.
We have to find out AF.
Sq. root of 72 + 242 = 25.
Question 2
Prabhu Deva danced and walked 10 m south from his house. Then he turned left and jogged 25 m and turned left and ran 40 m. He took rest there for ten minutes. After ten minutes he turned right and walked 5 m to reach his Dance College. In which direction is the dance college from Prabhu Deva’s house?
a) South East b) North c) North East d) North west
Answer : c) North East.
Solution :
Note : Actually, this is a simple question where there will be NO calculations involved, but a simple direction assessment is good enough. In some cases, you might start working out the distances which could eat up your time. Hence, it is important that you read the question well, understand the scope of the question and optimize your solving effort accordingly.
It can be seen that the dance college is in North East direction of Prabhu Deva’s house.
Question 3
Samuel Johnson and Ajith were standing 40 metres away. Samuel Johnson walked 5 metres towards east and Ajith walked 5 metres towards west. Samuel Johnson turned his left and walked 20 metres and Ajith turned right and walked 20 metres. Now Samuel Johnson turned to his left and walked further 5 metres. Ajith turned to his left and walked 10 metres. What is the distance between Samuel Johnson and Ajith?
a) 25 m b) 40 m c) 50 m d) none of these.
Answer : a) 25 m
Solution :
The entire travel paths of Samuel and Ajith are drawn as a diagram where the travel path of Samuel is ABCD and that of Ajith is A1B1C1D1.
Final distance between DD1 = initial distance - C1D1 - CD = AA1 - C1D1 - CD = 40 - 10 - 5 = 25